Math, asked by krrishna12, 1 year ago

In triangle ABC, there is a right angle at C. Here, CD is perpendicular to AB, and DE is perpendicular to CB. Prove that : CD^2 × AC = AD × AB × DE

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Answered by vishalraut22

congruent ACD & CDB, then all sides are equal by cptc. similarly congruent CED & BED then all sides will equal which proves the statement

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krrishna12: but how did u show that angle ACD and DCB are of 45°

vishalraut22: angle ACB is 90° & line CD is perpendicular which means it bisect the angle also

krrishna12: no, it is not necessary untill the triangle is isosceles one.

vishalraut22: if a line CD bisects the line AB into two equal parts then it also bisects the adjacent angle

krrishna12: yes but it is not said that AD = DB

vishalraut22: into two equal angles* 90° each

krrishna12: nhi samjha....

krrishna12: sir hindi kya?..

vishalraut22: haaa

krrishna12: sir apne jo bataya wo mujhe nhi samjhra

Answered by shrutimohta0220

here's your answer..

Hope it helped:-)

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shrutimohta0220: kuch nhi

shrutimohta0220: i was just answering ques

shrutimohta0220: hmm

shrutimohta0220: kis chiz ka

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