In triangle ABC ~to triangle PQR if Ab\PQ=1/3 then find the ar of triangle ABC\PQR
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1
Area of triangle ABC/Area of triangle PQR= (AB)square/(PQ)square
=> (1)square/(3)square= 1/9
Hence the ratios of the area of triangle ABC and PQR =1:9
=> (1)square/(3)square= 1/9
Hence the ratios of the area of triangle ABC and PQR =1:9
Answered by
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Given =AB/PQ=1/3
To find=ar(ΔABC)/ar(ΔPQR)
PROOF=
ar(ΔABC)/ar(ΔPQR)=(AB/PQ)square
[through theorem ]
Then, ar(ΔABC) /ar(ΔPQR)=(1/3)square
" " =1/9
To find=ar(ΔABC)/ar(ΔPQR)
PROOF=
ar(ΔABC)/ar(ΔPQR)=(AB/PQ)square
[through theorem ]
Then, ar(ΔABC) /ar(ΔPQR)=(1/3)square
" " =1/9
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