Question

In triangle ABC whose angle B is right angle AB = 24cm and BC = 7cm. So what will be the value of SinA.CosA

Answer 1

Find the hypotenuse:

a² + b² = c²

c² = 24² + 7²

c² = 625

c = √625

c = 25 cm

Find Sin A:

Sin θ  = opp/hyp

Sin A = 7/25

Find Cos A:

Cos θ  = adj/hyp

Cos A = 24/25

Answer: Sin A = 7/25 and Cos A = 24/25

Answer 2

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$

==> By pythogorus theorem

===>
$h {}^{2} = p {}^{2} + b {}^{2}$

===>
$h {}^{2} = (24) {}^{2} + (7) {}^{2}$

==>
$h {}^{2} = 576 + 49$

==>

$h {}^{2} = 625$
==> h = √625

===>
$\red{ \boxed{h = 25}}$

==>
$sin \theta = \frac{p}{h}$

==>
$\red{ \boxed{\underline{SinA = 7/25}}}$

===> Cos A = b/h

==> $\green{ \boxed{CosA = 24/25}}$