in triangle ABC,WRITE COSA+B/2 in term of angleS
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A + B + C = 180
A + B = 180 - C
Cos (A + B)/2= Cos (180 - C)/2
cos 180/2 - C/2
cos 90 - C/2
sin C/2
A + B = 180 - C
Cos (A + B)/2= Cos (180 - C)/2
cos 180/2 - C/2
cos 90 - C/2
sin C/2
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