In triangle ABC ,write tan A+B/2 in terms of angle C.
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as ABC is a triangle
therefore
A+B+C=180
A+B=180-C
divide by 2
(A+B)/2=90-C/2
apply tan
tan(A+B)/2=cotC/2
therefore
A+B+C=180
A+B=180-C
divide by 2
(A+B)/2=90-C/2
apply tan
tan(A+B)/2=cotC/2
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