Question

in triangle abc x=4y/3 and y=3z/8, findx,y and z

Answer 1

Answer:

x = 48°, y = 36°, z = 96°

Step-by-step explanation:

x+y+z = 180°

(4y/3) + y + z = 180°

(7y/3) + z = 180°

(7/3)(3z/8) + z = 180°

(7z/8) + z = 180°

15z / 8 = 180°

15 z = 180x8

z = 180x8/15 = 60 x 8 / 5 = 12 x 8 = 96°

y = 3z/8 = 36°

x = 4y/3 = 48°

Answer 2

Answer:

Question ⤵

in triangle abc x=4y/3 and y=3z/8, findx,y and z

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x+y+z = 180°

(4y/3) + y + z = 180°

(7y/3) + z = 180°

(7/3)(3z/8) + z = 180°

(7z/8) + z = 180°

15z / 8 = 180°

15 z = 180x8

z = 180x8/15 = 60 x 8 / 5 = 12 x 8 = 96°

y = 3z/8 = 36°

x = 4y/3 = 48°

Thanks..