Question

In triangle ABC, ZACB = 90°, AB = c
unit, BC = a unit, AC = b unit, CD is
perpendicular to AB and CD = p unit
prove that
1/p² = 1/a² + 1/b²​

Answer 1

Answer:

Step-by-step explanation:

Area of ΔABC =  1/2×base×height

Therefore, Area ΔABC = 1/2×a×b

Also, p is the height of the Δ

we can write area as

= 1/2×p×c

now, 1/2×p×c= 1/2×a×b

p= ab/c

Also, p^2=  (ab)^2/c^2

Also, c^2 = a^2 +b^2 (  ABC is right angle Δ)

Answer 2

Step-by-step explanation:

please see the attached for solution