in triangle ABCD AC =10 cm andBD =12cm ifP,Q,R,S are mid points of AB,Bc,CD andDA of square ABCD respectively then perimeter of square PQRS=
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P,Q,R and S are the mid-point of the sides AB,BC,CD and DA of a quadrilateral ABCD.
⇒ AC=BD
In △ABC,
P and Q are the mid-points of the sides AB and BC respectively.
∴ PQ∥AC ----- ( 1 )
And PQ=
2
1
×AC ------ ( 2 )
Similarly, SR∥AC and SR=
2
1
×AC ----- ( 3 )
From ( 1 ), ( 2 ) and ( 3 ) we get,
⇒ PQ∥SR and PQ=SR=
2
1
×AC ----- ( 4 )
Similarly we an show that,
⇒ SP∥RQ and SP=RQ=
2
1
×BD ----- ( 5 )
Since, AC=BD
∴ PQ=SR=SP=RQ [ From ( 4 ) and ( 5 ) ]
All sides of the quadrilateral are equal.
∴ PQRS is a rhombus.
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