In triangle ABD,angle ABC =45,Angle ACD=60,angle ADC=x Find x if BC:CD=1:2
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I think this is a wrong question broo....
animeshmishra0paqd2r:
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so ACD/,ADC = 2/1 ( ratio of sides equal to ratios of opposite angles of that sides)
ACD = 60
60/ADC = 2/1
2ADC= 60
ADC = 30 degrees
ACD = 60
60/ADC = 2/1
2ADC= 60
ADC = 30 degrees
How can ratio of side equal to ratio of angles??
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