In triangle ABD in which Angle 90 degree is angle dab and ac is perpendicular to bd prove that ad square is equal to bd multiply cd
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Answer:
Explanation:
in ΔADC and ΔDAB,
∠ADC=∠ADB (common)
∠DAB=∠ACD= 90° (AC⊥BD)
∴Bu AA Similarity criterion, ΔADB is similar to ΔCDA
⇒AD/CD= DB/DA= AB/AC (CPST)
⇒AD²= CD × BD
Hence, proved
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