In triangle ADE, angle ADE=140 dgerees and the points B,c lie on sides AD,AE respectively and points A,B,C,D,E are distinct. If lengths AB,BC,CD and DE are all equal, then the measure of triangle EAD is
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∠EAD = 10°
Step-by-step explanation:
Let say ∠EAD = x
=> ∠CAB = x as B lies on AD & C lies on EA
AB = BC
=> ∠ACB = ∠CAB = x
∠CBD = ∠ACB + ∠CAB
=> ∠CBD = 2x
∠CDB = 2x as BC = CD
=> ∠BCD = 180° - 2x - 2x
=> ∠BCD = 180° - 4x
∠ACB + ∠BCD + ∠DCE = 180° ( straight line)
=> x + 180° - 4x + ∠DCE = 180°
=> ∠DCE = 3x
∠DEC = ∠DCE = 3x ( as CD = DE)
Now x + 140° + 3x = 180°
=> 4x = 40°
=> x = 10°
∠EAD = 10°
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Answer:
Angle BCD = 140
Step-by-step explanation:
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