Question

in triangle ADE angle ADE is 35° and AED is 45° B and C are two points on DE such that triangle ABC is an is isoceles triangle find the angles of triangle ABC​

Answer 1

Step-by-step explanation:

In ∆ADE, D=35°, E=45°. A=?

A+D+E=180°,

35°+45°=A=180°

A=180°-80°=100°..

BAC=100/3.

In ∆ABC, B=C(angles equal to equal sides)

A+B+C=180°

100/3°+B+B=180°.

100°+3B+3B=3×180°

6B=540°-100°

6B=440°

B=C=440°/6=73.3°

A+B+C=180°.

A=180°-2×73.3

A=180°-146.6°

A=33.4°.

Answer 2

Answer:

okay no problem bro

concentrate on your studies

best of luck for board exams