Question

In triangle angel A=45°,angel B=35°,find angel C=(?)​

Answer 1

Given -

• In a triangle, two angles are given

→ ∠A = 45°

→ ∠B = 35°

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To find -

• Measure of ∠C.

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Solution -

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We know that, sum of all angles of a triangle is equal to 180°.

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Therefore,

→ ∠A + ∠B + ∠C = 180°

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→ 45° + 35° + ∠C = 180°

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→ 80° + ∠C = 180°

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→ ∠C = 180° - 80°

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→ ∠C = 100°

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Hence,

• Measure of the ∠C is 100°.

Answer 2

Question:-

In triangle angel A=45°,angel B=35°,find angel C=(?)

Given:-

$\angle a \rightarrow 45 \degree\\ \angle b \rightarrow35\degree\\ \angle c\rightarrow \: ?$

Solution:-

$\longrightarrow \: \angle a \: + \angle b + \angle c = 180\degree ( \because \: the \: sum \: of \: \triangle \: is \: 180\degree)\\ \longrightarrow 45\degree + 35\degree + \angle c = 180\degree \\ \longrightarrow80 \degree + \angle c = 180\degree \\\longrightarrow \angle c = 180\degree - 80\degree \\ \longrightarrow\angle c = 100\degree$

Final Answer :-

$\longrightarrow\angle c = 100\degree$