Question

IN TRIANGLE ANGLE( A-B=12°,B-C=27)ANGLEC=?

Answer 1

Answer:

<C=38°

Step-by-step explanation:

Given, <A-<B=12°,<B-<C=27°

To Find: <C=?

Soln|<A-<B=12°

=> <A=12°+<B ------(i)

<B-<C=27°

=> <B=27°+<C -------(ii)

Now, In triangle ABC

<A+<B+<C=180° [ASPT]

(12°+<B)+(27°+<C)+<C=180° [from (i) & (ii)]

12°+27°+<C+27°+<C+<C=180°

3<C+66°=180°

3<C=180°-66°

<C=114°/3

<C=38°