In triangle angle BAC equal to 90 degree and ad perpendicular to BC then
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PROOF: <CAD + <DAB = 90 deg (given)
Also, < DAB + <DBA = 90 deg ( as given that triangle ADB is a right triangle)
=> <CAD + <DAB = <DAB + <DBA ( by above 2 statements)
=> <CAD = <DBA …………………. (1)
Similarly, <ACD = <DAB ……………(2)
=> triangle ADC ~ triangle BDA ( by AAA similarity criterion)
=> AD/BD = DC/AD ( corresponding sides of similar triangles)
=> AD^2 = BD x CD ( by cross multiplying)
[Proved]
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