Math, asked by diyagandhi, 1 year ago

in triangle aob angle aob =90 ac =bc oa=7 oc=12.5.find area of the triangle

diyagandhi: In triangle aob angle aob =90 ac =bc oa=7 oc=12.5.find area of the triangle

sabarinathcs: WHAT IS C??

sabarinathcs: IT IS BETTER YOU PROVIDE A FIGURE

diyagandhi: HOW TO PROVIDE A FIGURE

diyagandhi: PLEASE GIVE ANSWER

sabarinathcs: YOU EDIT YOUR QUESTION

sabarinathcs: THERE WILL BE A ICON JUST BELOW YOUR QUESTION!!

Answers

Answered by Meww

AC=BC=OC=12.5 (Mid-point of the hypotenuse of a right triangle is equidistant from the vertices)
Area of Triangle = 1/2*B*H
= 1/2 * 25 * 12.5 = 156.25 unit²

sabarinathcs: but it is 7 no

Meww: No.. b = 25

Meww: AC=BC=OC=12.5 so add ac n bc to get the base = 25

sabarinathcs: ok

sabarinathcs: how OC =AC=BC

sabarinathcs: you are in which class??

Meww: 9th

Meww: AC=BC=OC=12.5 (Mid-point of the hypotenuse of a right triangle is equidistant from the vertices)

Meww: read my answer

sabarinathcs: ok thanq frd

Answered by sabarinathcs

As, AC = BC
and OC is the median (line drawn from the mid point to the opposite vertice)
Area of a triangle = $\frac{1}{2} bh$
= $\frac{1}{2}$ ×25×12.5= 156.25unit²