in triangle BAC,<c=3 <b=2(<A+ <B) if <A=x and <B=y then form the pair os linear equation and find <A <B <C.
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<C=3B=2(<A+<B)
therefore, <B=C/3
<C=2A+2B
therefore, 2A+2B-C=0 ....(1)
we also know that ,
<A+<B+<C=180 .....(2)
multiply eq. (2) by 2 and subtract it from eq. (1)
after subracting we get,
- 3<C= -360
<C= -3/-360
<C= 120
therfore, <B= 120/3= 40
<A= 180-<C+<B
<A= 20
hence, now all the angles are known to you
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