In triangle,cos(P+R)=0.what is angle Q equal to
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cos(p+r)=0
cos(p+r)=cos90
therefore p+r=90
therefore angle q=90
correct option is D
cos(p+r)=cos90
therefore p+r=90
therefore angle q=90
correct option is D
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Cos (P +R) = 0.
cos (P+ R) = cos 90
P+R = 90. . eqn 1
In triangle PQR,
By angle sum property,
P + Q + R = 180°
Q = 180 - 90. .(from eqn 1)
Q = 90°
hence correct option is (D) 90°.
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