In triangle de paralle to bc ad-4, db-10, ae-5 find ac
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According to BPT,
AB/AD = AC/AE
AC = (AB×AE) / AD
AC = ((AD+DB) ×AE) / AD
AC = (14×5)/4 = 70/4 = 17.5
AB/AD = AC/AE
AC = (AB×AE) / AD
AC = ((AD+DB) ×AE) / AD
AC = (14×5)/4 = 70/4 = 17.5
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