Question

in triangle DEF ,angle DFE=90° FG perpendicular to ED if GD =8 FG=12 find EG , FD ,EF​

Answer 1

Answer:

Step-by-step explanation:

In right Δ DFG, GD = 8 AND FG = 12

⇒$DF^{2}$ = $FG^{2} + GD^{2}$ (SinceFG perpendicular to ED )

⇒FD = $\sqrt{GD^{2} + FG^{2} }$

         =$\sqrt{8^{2}+12^{2} }$

         =$\sqrt{64 + 144} =\sqrt{208} = 4\sqrt{13}$