In triangle DEF ,angle L =90⁰ EN is perpendicular to DF .DN =5cm DF=45cm then DE=___
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Given : In triangle DEF ,angle E =90⁰ EN is perpendicular to DF .DN =5cm DF=45cm
To Find : DE
Solution:
∠DNE = ∠ENF
∠EDN = ∠FEN ( 90° - F)
∠DEN = ∠EFN ( 90° - D)
ΔDNE ≈ Δ ENF
=> DN/EN = EN/FN
FN = DF - FN = 45 - 5 = 40 cm
=> 5/EN = EN/40
=> EN² = 200
=> EN = 10√2
DE² = DN² + EN²
=> DE² = 5² + 200
=> DE² = 225
=> DE = 15 cm
DE = 15 cm
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