Question

In triangle DEF,DM and EN are two medians.Prove that 3(DF+EF)>2(DM+EN).

Answer 1

Answer:

3(DF + EF) > 2(DM + EN)

Step-by-step explanation:

in Δ DMF

DF + FM > DM  ( Sum of two sides of triangle > third sides)

=> 2(DF + FM ) > 2DM

=> 2DF + 2FM > 2DM

DM id median => 2FM = EF

=> 2DF + EF > 2DM    Eq1

Similarly

in ΔEFN

EF + FN > EN

=> 2EF + 2FN > 2EN

=> 2EF + DF > 2EN   Eq2

Eq1  + Eq 2

=> 2DF + EF + 2EF + DF  > 2DM  + 2EN

=> 3DF + 3EF > 2(DM + EN)

=> 3(DF + EF) > 2(DM + EN)

QED

Proved

Answer 2

Answer:

y2gwybeunzkiuuhyegbwh ygckvjcg gj jgxhd ngxjg yfufhc gxjgxjgxgk chxb gxgmx xz San

zd

Step-by-step explanation:

mcgcych mhvjch ycgmycncy f c

.yiccycyicycoyycycyc

h iyiccycocyctc

vhl g g yov