in triangle given below prove that
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angle PQR = angle PTR - angle QPT -----(i)
angle PRS = angle QPR + angle PQR ----(ii)
Adding (i) and (ii)
angle PQR + angle PRS = angle PTR - angle QPT + angle QPR + angle PQR
angle PQR + angle PRS = angle PTR - angle QPT + 2angle QPT + angle PQR ( since angle QPR = angle QPT and angle QPR = angle QPT + angle QPR which equals 2angle QPT)
angle PQR + angle PRS = angle PTR + angle QPR + angle PQR
angle PQR + angle PRS = angle PTR + angle PTR
( since angle PTR is exterior angle of ∆QPT , •°• it equals to sum of two opposite interior angles , in this case , it equals angle QPT + angle PQR , also angle QPT = angle QPR , said above)
•°• angle PQR + angle PRS = 2 angle PTR
Hence , Proved
angle PRS = angle QPR + angle PQR ----(ii)
Adding (i) and (ii)
angle PQR + angle PRS = angle PTR - angle QPT + angle QPR + angle PQR
angle PQR + angle PRS = angle PTR - angle QPT + 2angle QPT + angle PQR ( since angle QPR = angle QPT and angle QPR = angle QPT + angle QPR which equals 2angle QPT)
angle PQR + angle PRS = angle PTR + angle QPR + angle PQR
angle PQR + angle PRS = angle PTR + angle PTR
( since angle PTR is exterior angle of ∆QPT , •°• it equals to sum of two opposite interior angles , in this case , it equals angle QPT + angle PQR , also angle QPT = angle QPR , said above)
•°• angle PQR + angle PRS = 2 angle PTR
Hence , Proved
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