Question

In triangle MNS, A and B are points on the sides MN,NS
respectively. AN=1/2MN,BS=1/2MS, then AB is---to NS

@ Not perpendicular,(b)Parallel (c) perpendicular(d)not parallel​

Answer 1

Solution :-

In ∆MNS we have,

→ AN = 1/2(MN)

→ AN = (1/2)(MA + AN)

→ AN = (1/2)MA + (1/2)AN

→ AN - (1/2)AN = (1/2)MA

→ AN[1 - (1/2)] = (1/2)MA

→ (1/2)AN = (1/2)MA

→ AN = MA

so, A is mid point of MN .

similarly,

→ BS = (1/2)(MS)

so, B is mid point of MS .

since AB is a line segment joining the mid points of two sides of ∆MNS .

therefore,

→ AB || NS { According to Mid point theorem the line segment joining the mid points of two sides of a triangle is parallel to the third side . }

Hence, Option (b) parallel is correct answer.

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