In triangle opq right angle at p op=7 and oq-pq=1cm the the values of sinq is
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p=90°
(oq)²=(op)²+(pq)²
=7²+1²
oq =√50
oq =5√2
sin q= op/oq
= 7/5√2
(oq)²=(op)²+(pq)²
=7²+1²
oq =√50
oq =5√2
sin q= op/oq
= 7/5√2
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0
This is the value of sinQ.
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