Question

In triangle opq right angled at p, op =7

Answer 1

Answer:

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Answer 2

In $\triangle$ OPQ, we have

OQ²= OP²+PQ²

(1+PQ)²=OP²+PQ²

1+PQ²+2PQ = OP²+PQ²

1+2PQ =7²

PQ = 24 cm

OQ= 1+25 cm

$sinQ =\bf \frac {7}{25} \\ \\ cos Q =\frac {24}{25}$