Question

In triangle OPQ right angled at P,
OP=7cm, OQ-PQ= 1 cm.
Determine of sinQ and cosQ

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Answer 1

Answer:

sinQ = opp/hyp = 7/25

cosQ = adj/hyp = 24/25

Step-by-step explanation:

Let's assume OQ as c, PQ as b and OP as a.

Given - (OQ - PQ = 1cm or c - b = 1 )

Now, as we know OP is 7cm and OQ is 25 and we have to find QP.

So, for that we are gonna use Pythagoras' way.

a² + b² = c²

[ ∵ c-b = 1

c = b + 1]

7² + b² = (b + 1)²

49 = 2b² + 1

24 = b ( QP )

Now,

sinQ = opp/hyp = 7/25

cosQ = adj/hyp = 24/25

Answer 2

In $\triangle$ OPQ, we have

OQ²= OP²+PQ²

(1+PQ)²=OP²+PQ²

1+PQ²+2PQ = OP²+PQ²

1+2PQ =7²

PQ = 24 cm

OQ= 1+25 cm

$sinQ =\bf \frac {7}{25} \\ \\ cos Q =\frac {24}{25}$