Question

in triangle P Q R right angle at Q, if P Q = 3 cm and PR=6 cm then R is

Answer 1

Step-by-step explanation:

In ∆PQR, right angled at Q, PQ = 3cm, PR = 6cm, how do you find ∠P & ∠ R?

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Given that :<Q=90,

PQ=3

PR=6

Now by applying sine rule :

SinR/PQ=SinQ/PR

By putting values from the question we get

SinR/3=sin90/6

On solving

SinR=1/2

<R=30

By applying property of right angle

<p+<q+<r=180

<p+90+30=180

<p=180–120

<p=60

So answer is <p $ <R is 60 $30

Answer 2

Solution:-

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From the figure, we have

CosP= adjacent side / hypotenuse

= 3/6

=1/2

We know that, Cos60°=1/2

CosP= Cos60°

therefore, AngleP=60°

∆PQR is the right angles at Q

therefore, AngleQ= 90°

In ∆ PQR,

Angle P+Angle Q+Angle R=180°

➪60°+90°+Angle R=180°

➪150°+Angle R=180°

➪Angle R =180°-150°

➪Angle R= 30°

Therefore, Angle R= 30°

Hope it will help you.....