Question

in triangle PAN ,angle A=90 .if sin p =21/29 1) find the length of AP 2) find the value of sec N 3) find the value of cot p​

Answer 1

Step-by-step explanation:

if, sin P = 21/29

Then, AN = 21 & NP = 29.

so, AP =

$\sqrt{ {29}^{2} - {21}^{2} } \\ = \sqrt{841 - 441} \\ = \sqrt{400} \\ = 20$

(a) The Length of AP = 20 unit...

(b) The Value of Sec N

= NP/AN

= 29/21

(c)The Value of Cot P

= AP/AN

= 20/21

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Answer 2

Answer:

sin tera is always equal to adj/hyp

so sinteta he gave 21/29 so ap= 20

and value of secteta is =pn/ap

so cotteta=29/20

value of corp=20/21 as the cot tera= 1/tanteta

hope this answer is helpful