Question

In triangle POR, right angle at Q, PR + QR = 25cm and PQ = 5cm. Determine the value of sin P, cos P and tanP.

Answer 1

Answer:

$\huge\bf\red{QuesTion:-}$

In triangle POR, right angle at Q, PR + QR = 25cm and PQ = 5cm. Determine the value of sin P, cos P and tanP.

$\huge\bf\red{AnswEr:-}$

Given PR + QR = 25 , PQ = 5

PR be x.  and QR = 25 - x 

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x = 13

 

 PR = 13 cm

QR = (25 - 13) cm = 12 cm

sin P = QR/PR = 12/13

cos P = PQ/PR = 5/13

tan P = QR/PQ = 12/5

Answer 2

Answer:

Explanation:Given PR + QR = 25 , PQ = 5

PR be x.  and QR = 25 - x  

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x = 13

PR = 13 cm

QR = (25 - 13) cm = 12 cm

sin P = QR/PR = 12/13

cos P = PQ/PR = 5/13

tan P = QR/PQ = 12/5