Question

In triangle POR, right angle at Q, PR + QR = 25cm and PQ = 5cm. Determine the value of sin P, cos P and tanP. @shreeya21

Answer 1

Given:

∠Q = 90°

PR + QR = 25cm

PQ = 5cm

To Find:

Values of sin P, cos P and tan P.

Solution:

Let assume the length of QR = x cm

And PR = (25 - x) cm

Now,

By using Pythagoras Theorem,

RP² = RQ² + QP²

⟹(25−x)

2 =(x)

2

+(5)

2

⟹625−50+x

⟹−50x=−600

⟹50x=600

⟹x= 50/600

⟹x=12

Then,

QR = x = 12cm

PR = 25 - x = 25 - 12 = 13cm.

∴ sin P = QR/PR = 12/13

cos P = QP/PR = 5/13

and tan P = QR/PQ = 12/5.

Answer 2

Answer:

In triangle POR, right angle at Q, PR + QR = 25cm and PQ = 5cm. Determine the value of sin P, cos P and tanP.

Given PR + QR = 25 , PQ = 5

PR be x.  and QR = 25 - x 

Pythagoras theorem ,PR2 = PQ2 + QR2

x2 = (5)2 + (25 - x)2

x2 = 25 + 625 + x2 - 50x

50x = 650

x =13

Explanation:

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