Question

in triangle pq parallel to bc AP=x-2,PB=x-3,AQ=x-3,QC=x-5 find X​

Answer 1

Answer:

x= 1

Step-by-step explanation:

since pq parallel to bc

therefore AP/PB= AQ/QC

x-2/x-3= x-3/x-5

(x-2) (x-5) = (x-3) (x-3)

x square - 5x - 2x + 10= x square - 3x - 3x + 9

- 7x + 10 = - 6x + 9

- 6x + 7x = 10 -9

x = 1