In triangle PQR , AB║QR find x (in cm).
PA =2.4cm , PB= 3.2cm , AQ=3.6cm , BR=4.8cm , AB=2cm , QR= x cm
Answers
Given : in ΔPQR
PA = 2.4 cm , QA = 3.6 cm
PB = 3.2 cm , BR = 4.8
AB = 2 cm QR = x cm
To Find : Find Value of x in cm
a) 4
b) 5
c) 6
d) 8
Solution:
PA = 2.4 cm , QA = 3.6 cm
PB = 3.2 cm , BR = 4.8
PA/QA = 2.4/3.6 = 2/3
PB/BR = 3.2/4.8 = 2/3
=> PA/QA = PB/BR
Using converse of Thales theorem BPT
AB || QR
Comparing ΔPAB & ΔPQR
∠P = ∠P Common
∠A = ∠Q ( corresponding angles as AB || QR)
∠B = ∠R ( corresponding angles as AB || QR)
=> ΔPAB ≈ ΔPQR
=> PA/PQ = AB/QR
PQ = PA + QA = 2.4 + 3.6 = 6
=> 2.4/6 = 2/x
=> x = 12/2.4
=> x = 5
value of x (in cm) is 5
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Answer:
5 cm
Step-by-step explanation:
Solution:
PA = 2.4 cm , QA = 3.6 cm
PB = 3.2 cm , BR = 4.8
PA/QA = 2.4/3.6 = 2/3
PB/BR = 3.2/4.8 = 2/3
=> PA/QA = PB/BR
Using converse of Thales theorem BPT
AB || QR
Comparing ΔPAB & ΔPQR
∠P = ∠P Common
∠A = ∠Q ( corresponding angles as AB || QR)
∠B = ∠R ( corresponding angles as AB || QR)
=> ΔPAB ≈ ΔPQR
=> PA/PQ = AB/QR
PQ = PA + QA = 2.4 + 3.6 = 6
=> 2.4/6 = 2/x
=> x = 12/2.4
=> x = 5
Value of x (in cm) is 5