In triangle pqr and triangle xyz it is given that triangle pqr is similar to triangle xyz angle y+anglez equal to 90 degrees and xy:yz=3:4 then find the ratio of sides in triangle pqr
Answers
Answer:
Given that, ∆pqr ~ ∆xyz, so we have
Since the two triangles are similar, therefore, they will have their corresponding angles congruent and the corresponding sides in proportion.
pq/xy = qr/yz = pr/xz …… (i)
and,
∠p = ∠x ….. (ii)
also,
xy:yz = 3:4 …… (iii) [given in the question]
Consider ∆xyz,
∠y + ∠z = 90° [given in the question]
∴ ∠x + ∠y + ∠z = 180° [∵ sum of angles of a triangle is 180°]
⇒ ∠x = 180° - 90° = 90°
∴ ∠p = 90° ….. (iv) [from eq. (ii)]
Also,
xy:yz = 3:4 and ∠x is a right angle, therefore we can say that
⇒ yz is hypotenuse
By using the Pythagoras theorem, we get
xz =
⇒ xy : yz : xz = 3 : 4 : √7
Similarly,
since Δ PQR is a similar triangle to Δ XYZ
From (iv), we have p is a right angle
⇒ qr is the hypotenuse
⇒ pr : qr : pq = 3 : 4 : √7
Hence, the ratio of the sides pr, qr & pq in the triangle pqr is 3 : 4 : √7.
Answer:
Given,
Δxyz ≅ Δpqr
PQ=4cm ; QR=5cm ; XY=6cm
⇒\frac{PQ}{XY}
XY
PQ
= \frac{QR}{YZ}
YZ
QR
[corresponding sides of similar triangles are in the same ratio]
⇒ \frac{4}{5} = \frac{6}{YZ}
5
4
=
YZ
6
⇒YZ = \frac{30}{4}YZ=
4
30
⇒YZ = 7.5 cm