in triangle pqr, angle p=30 , angle q=90 , angle r = 60 and pr= 14 cm then pq = ?
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since q is right angled so this is right angle triangle
so sin60=pr/14
=√3/2=pr/14
=pr=7√3
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Given : in triangle pqr, angle p=30°, angle q=90° , angle r = 60°
pr= 14 cm
To Find: pq
Solution:
∠q = 90°
Hence triangle pqr is right angled at q
and side opposite to angle q is Hypotenuse
Hence pr is hypotenuse = 14 cm
Cos p = Side adjacent to angle p / hypotenuse
=> cos 30° = pq/pr
=> √3/2 = pq/14
=> pq = 7√3
length of pq is 7√3
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