In triangle PQR angle p =80 degree, angle Q=60 degree. find the greatest and the smallest side of the triangle
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Answer:
Given,
Triangle PQR
P = 80
Q = 60
R = x
We know that all angles of a triangle is 180°
According to the question,
/P + /Q + /R = 180°
80 + 60 + x = 180
=> 140 + x = 180
=> x = 180 - 140
x = 40°
Greatest side or angle = /P = 80°
Smallest side or angle = /R = 40°
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