Question

in triangle PQR , angle PQR =90° find sin p and cos p

pls guys pls give me answer I need help​

Answer 1

Answer:

sin p = $\frac{QR}{PQ}$ ;   cos p = $\frac{PQ}{PR}$

Step-by-step explanation:

The answer is correct.

Answer 2

Answer:

the angle of p=30° and the all angles are 30°p son coz p