In triangle PQR,angle PQR=90°,PQ=6,&PR=10,then find the length of seg.QR
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Answered by
0
Answer:
PR= 10
Step-by-step explanation:
PQ^2 + QR^2 = PR^2
6^2 + 8^2 = PR^2
36+64=100
PR^2=100
PR= V100
PR= 10
ArnabBro000
PR= 10
Step-by-step explanation:
PQ^2 + QR^2 = PR^2
6^2 + 8^2 = PR^2
36+64=100
PR^2=100
PR= V100
PR= 10
ArnabBro000
Answered by
0
Step-by-step explanation:
In triangle PQR
measure anglanQ=90°
(PR)2=(PQ)2+(QR)2
(10)2=(6)2+(QR)2
100=36+(QR)2
100-36=(QR)2
64=(QR)2
8=QR
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