In triangle pqr, angle q=90, find, pr, if pq=8cm and qr=6cm and the area of triangle qmr
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Answer:
10cm
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using Pythagoras theorem we have
pr²= pq²+qr²
pr²=(8cm)²+(6cm)²
pr²=64cm²+36cm²
pr=√100cm²= 10cm
now area of the triangle= 1/2 base *altitude
= 1/2 *6cm * 8cm
=24cm²
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