In triangle PQR , angle Q = 90° and QS perpendicular PR if PA = 32cm , SR = 8cm find QS
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In triangles PQS and PQR
∠P is common to both.
and ∠PSQ=∠PQR
Triangles PQS and PQR are equiangular
∴PQPS=QRQS
or, PS=QRPQ⋅QS ...(i)
Again, triangles QRS and PQR are equiangular
∴QRSR=PQQS
or, SR=PQQS⋅QR ...(ii)
From eqns. (i) and (ii)
SRPS=QRPQ⋅QS⋅QR⋅QSPQ=QR2PQ2
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