In triangle PQR angle Q=90°,angle P=45° ,QR=5cm what is the length of PR?
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Given :-
- In ∆PQR, ∠Q = 90° .
- ∠P = 45° .
- QR = 5 cm.
To Find :-
- Length of PR = ?
Solution :-
In ∆PQR,
→ ∠P + ∠Q + ∠R = 180° (angle sum property of a ∆.)
→ 45° + 90° + ∠R = 180°
→ 135° + ∠R = 180°
→ ∠R = 180° - 135°
→ ∠R = 45° .
so,
→ ∠R = ∠P .
now, we know that,
- Sides opposite to equal angles are equal in length .
therefore,
→ QR = QP = 5 cm.
hence,
→ PR = √(QR² + QP²) (by pythagoras theorem.)
→ PR = √(5² + 5²)
→ PR = √(25 + 25)
→ PR = √(50)
→ PR = 5√2 cm. (Ans.)
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