In triangle PQR, angle Q = 90°, PQ = 5√2 cm ,
PR = 10cm then find angle P = ?
Answers
Answered by
1
Answer:
R.E.F.image
In △PQR,∠PQR=90
∘
BY Pythagoras theorem,
PR
2
=PQ
2
+QR
2
⇒(5)
2
=PQ
2
+(4)
2
⇒(5)
2
−(4)
2
=PQ
2
⇒PQ
2
=25−16
⇒PQ
2
=9
⇒PQ=
9
⇒PQ=3
tanR=
QR
PQ
=
4
3
.
Step-by-step explanation:
R.E.F.image
In △PQR,∠PQR=90
∘
BY Pythagoras theorem,
PR
2
=PQ
2
+QR
2
⇒(5)
2
=PQ
2
+(4)
2
⇒(5)
2
−(4)
2
=PQ
2
⇒PQ
2
=25−16
⇒PQ
2
=9
⇒PQ=
9
⇒PQ=3
tanR=
QR
PQ
=
4
3
.
Answered by
1
Answer:
45
Step-by-step explanation:
draw an appropriate RAT
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