Question

in triangle PQR ,angle Q=angle R=45°,and QR=10 find its area​

Answer 1

Step-by-step explanation:

sides pq=qr as angles are equal (45°)

we know that sum of all the angles of a traingle is 180°.

so the angle p is 90°.

let side pq be a cm.

Using Pythagoras Theorem:-

a²+a²=(10)²

2a²=100

a²=100/2=50

a=√50=5√2cm

Area of the triangle=1/2×base×height

=1/2×5√2×5√2=1/2×50=25 cm²

Here is ur solution..

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