Question

in triangle PQR, angle QPR =90 degree, then find PQ^2​

Answer 1

Applying Pythagoras theorem

Hypotenuse² = Perpendicular² + Base²

if ,

• PQ = Base = 6
• PR = Perpendicular = 5
• QR = Hypotenuse = 4

Then ,

• QR² = PR² + PQ²
• PQ² = QR² - PR²
• PQ² = 4² - 5²
• PQ² = 16 - 25
• PQ² = - 9

In another way ,

• PQ² = 6² = 36