in triangle pqr, angle rqp is equal to 35 degree and pq is equal to pr. what will be the value of qpr?
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Given, in △PQR,PQ=PR
Therefore, △PQR is an isosceles triangle with equal base angles, ∠Q=∠R.
Exterior ∠R=100
o
Therefore, PRQ=80
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As angles Q and R are equal, ∠PQR=80
o
∠P+∠Q+∠R=180
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∴∠P=20
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i.e. ∠QPR=20
o
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