in triangle PQR angleP =angleQ +angleR find the value of the angleP
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HEYA!!!!
Given,
<P = < Q + < R
Sum of all angles in a triangle = 180
ATP,
< P = < Q + < R
let < Q and < R = 45
Therefore, < Q + < R = 45 + 45 = < P = 90...
HOPE THIS HELPS U. .
Given,
<P = < Q + < R
Sum of all angles in a triangle = 180
ATP,
< P = < Q + < R
let < Q and < R = 45
Therefore, < Q + < R = 45 + 45 = < P = 90...
HOPE THIS HELPS U. .
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