Question

In triangle PQR given LQ = 90° Q-S-R then prove that QR² + PS²= PR² + QS²​

Answer 1

Step-by-step explanation:

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Answer 2

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Given

In triangle PQR

angle Q=90°

to prove

QR² + PS²= PR² + QS²

proof

By using pythagoras property

PR²=PQ²+QR²

since,S divides QR line

PR²=PQ²+(QS+SR)²

PR²=PQ²+QS²+SR²+2(QS)(SR)

QR² + PS²= PR² + QS²

$hence \: proved$