Question

In triangle PQR if 3sinp+4cosq=6 and 4sinq+3cosp =1 then find anglePRQ

Answer 1

square both the equations and add both them.
u will get 25+ 24(sinpcosq+cospsinq)=37
24(sin(p+q))=12
sin(p+q)=0.5
hence, p+q=30 or 150
if p+q=30,
then sin p
3sin p+4cosq
which is incorrect according to the given question
hence p+q=150
and R=30 DEGREES.
HOPE THIS IS CLEAR

Answer 2

Answer:

π/6

Step-by-step explanation:

3sinP+4cosQ=6 -----(1)

4sinQ+3cosP=1 -----(2)

square and add both the equations,

so we get,

p+q=150

now apply theorem of sum of angles of triangle,

P+Q+R=180

we know that, P+Q=150

so,

R=180°-150°

R=30°

Therefore,

R=¶/6