Question

in triangle pqr if angle Q is equal to 40 degree and Angle is equal to 72 degree then find the shortest the largest sides of the triangle

Answer 1

first find the rest angle
Acorrding to question
angle P+angleQ +angle R=180(by angle traingle sum property)
40+75+angleR=180
angle R=180-115=65
Now, In ΔPQR
angle P=72>angleR>angle Q
there for largest side is PQ
hope it's helpfull

Answer 2

Answer:

∠Q

Step-by-step explanation:

By the triangle sum property:

The sum of all three sides of a triangle is always 180°.

Here we have already given two of the angles.

Let the third angle of the triangle is 180°.

Thus, 40° + 72° + x = 180°

⇒ x = 180 - 112 = 68°

Thus, the smallest side of the triangle PQR is ∠Q which is equal to 40°