Question

in triangle PQR,if LPQR=90°,state the pythagorem relation in the triangle.​

Answer 1

Answer:

(PR)²=(PQ)²+(QR)²

Step-by-step explanation:

H²=P²+B²

H=PR , P=PQ , B=QR

Hence , (PR)²=(PQ)²+(QR)²

Answer 2

Answer:

$(PQ)^{2} + (QR)^{2} = (PR)^{2}$

Step-by-step explanation:

IN THE GIVEN FIGURE,

IF ∠PQR = 90⁰ ,

THEN IT IS CLEAR THAT THE SIDES OF THE RIGHT ANGLED TRINAGLED ΔPQR SO OBTAINED ARE PQ AND QR RESPECTIVELY....

ACCORDING TO PYTHAGORA'S THEOREM ,

PQ² + QR² = PR²

WHERE PR OBTAINED IS THE HYPOTENUSE...

HOPE THAT IT HELPS..